kaitoufion Posted April 30, 2006 Share Posted April 30, 2006 Hello, I just finished a Chemistry lab and now I need to write up a report which I am having some difficulties:-( I really hope you guys can help me out here coz it's duing tomorrow :'( Experiment 1: H2O2 + H2SO4 + KMnO4 -> little bubbles (no change in colour) Then I'm required to write down its equations which is set out like this: Oxidation: Reduction: Overall: Can someone please tell me how to write the equations in this format please??? Experiment 2: H2O2 + KMnO4 -> bubbles & brown precipitate Again I'm required to write down the equations in the above format:-( Can someone help me here please??? THANK YOU SO MUCH!!! >.< Link to comment Share on other sites More sharing options...
woelen Posted April 30, 2006 Share Posted April 30, 2006 I'm not going to give you all answers, but with my hints you should be able to answer your questions. 1) In both cases, hydrogen peroxide acts as a reductor. Oxygen goes from oxidation state -1 to 0. Try to determine the half-reaction for hydrogen peroxide, acting as reductor. One of the products is oxygen. 2) In acidic environments, the permanganate is converted to colorless Mn(2+) ions. What is the half-reaction for permanganate to Mn(2+) in acidic environments? 3) In neutral or weakly alkaline environments, the permanganate is converted to brown MnO2. What is the half-reaction for permanganate to MnO2 in neutral/alkaline environments? Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now