kaitoufion Posted April 30, 2006 Posted April 30, 2006 I got this question from my Chem lab: Al(NO3)3 + Na2CO3 -> white precipitates White precipitate + HNO3 -> bubbles & precipitates dissolved Can someone kindly tell me what does the Ionic Equation for the above actions would look like??? Because I'm having difficulties in writing its Ionic Equations >.< Thank you so much!
chuinhen Posted April 30, 2006 Posted April 30, 2006 Actually there is no Redox reaction takes place !!! So : 1) 2 Al 3+ + 3 CO3 2- -----> Al2(CO3)3 ( white ppt ) 2) CO3 2- + 2H+ -----> CO2 (effervesence ) + H2O
Primarygun Posted April 30, 2006 Posted April 30, 2006 2) CO3 2- + 2H+ -----> CO2 (effervesence ) + H2O A tiny difference from my answer. In my region, we would put down the precipitate instead of just the ion.
kaitoufion Posted April 30, 2006 Author Posted April 30, 2006 Oh Thank you so much~!! That's great help!
wpenrose Posted April 30, 2006 Posted April 30, 2006 1) 2 Al 3+ + 3 CO3 2- -----> Al2(CO3)3 ( white ppt ) 2) CO3 2- + 2H+ -----> CO2 (effervesence ) + H2O The precipitate loses CO2, and the Al(OH)3 begins to lose water, forming polymers of aluminum oxide in a meshwork molecular structure, until in the limit, only Al2O3 would be left. It won't go all the way to alumina unless the water is removed by filtering and heating. Dangerous Bill
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