Infrasound

[Guest Dr_Cole]

Hi, could some one please give me a detailed and complex description of what infrasound is?

 

P.S. Please when answering could you make your reply as complex as possible so i get all the information available also could you please state you name and the degrees you hold for future reference

[fafalone]

Infrasound is just sound with a frequence below the threshold of hearing for any of the hair cells in our ears. Typically this is anything below 20Hz. It's the opposite of ultrasound, which is above the highest frequence we can hear, which is about 20kHz

[VendingMenace]

Please when answering could you make your reply as complex as possible so i get all the information available

 

Infrasound is a name given a set of presure waves, {of the form, (only for 1 dim, but the abstrction to 3 dim is trivial, i feel) is, [(d^2s)/(dt^2)=(dP)/(dp)*(d^2s)/(dx^2)], where s is a displacement factor, t is time, x is distnace, P is pressure, and p is density. Also, only dP and dp are derivatives, while the reast are partial derivatives} with frequency lower than that wich is detectable by human ears. For particulare ears, you may consider them as closed pipes with lenghth L as a resonable approximation if you wish to do a freestanding wave calcualtion. In this calculation, you will need to use the equation lambda =4L/(2n-1). These waves propagate with speed v= sqrt[dP/(dp)]. Of course these waves, being pressure waves are able to propagate though most mediums even those that so not sustain sheer forces. Of course what in infrasound also dedends on your relative frame of refence. If you either you or the source is moving you will expreince a wavelength shift, and you shlould take this into acount. If the source is moving we find lemba'=(1-v'/v)(lambda). If you are moving we find (frequency)' = (1-V''.V'/v)(frequency). Combining the two we arrive at the equation for both the source and the observer moving.

 

Of corse there is more, we can concern ourselves with the intensity and energy of the sound. Intesity = power/amplitude Were power is found by crossing the force of the sound pressure front with the volcity of the wave.

 

Well, i think that is enought for now, don't you??

 

also could you please state you name and the degrees you hold for future reference

 

WEll, my name is vendingmenace and i hold both 360 degress and 98.6 degrees. Unless we are in celcius scale. Of course in Kelvin i don't hold any degrees, cuase that would be improper. Also, if this post is too much of a jacka$$ed post, i may be geteting the third degree. It a good thing i wear that one deoderant, what is it called??? thats right, degree.

[YT2095]

and it`s usualy taken from the sinusiodal waveform as those with sharper "spikes" create second/third etc... harmonics.