Simplify with a square root

[kaseyface]

My problem is

 

Simplify: [use absolute value symbols if necessary]

 

Squareroot 75a2b3c.

[timo]

Is that a different display system than the decimal one or is that [math] \sqrt{75 a^2 b^3 c} [/math] ?

[kaseyface]

It's that problem you wrote. I couldn't figure out how to write my problem like that. Sorry if it was confusing!

[timo]

The key to your problem is using the fact that [math] \sqrt{xY} = \sqrt{x} \cdot \sqrt{Y} [/math]. Using that, try to pull out as many factors as possible. I´ll give you a first step, you´ll have to do the others yourself:

[math] \sqrt{75a^2b^3c} = \sqrt{b^2} \cdot \sqrt{75a^2b^1c} = b \sqrt{75a^2bc} [/math]

[JustStuit]

If you still have trouble, separate it out to [math]\sqrt{(25)(3)a^2b^2bc}[/math] and see if that helps.