Renegade Posted May 23, 2006 Posted May 23, 2006 Need some help guys! 1) Equation: N2 + 3H2 ---> 2NH3 (N subscript 2 + 3 (H subscript 2) equals 2NH(subscript 3) Problem: What volume of NH3 is produced if 25.0g of N2 is reacted with an excess of H2? Can someone explain this one... and: 2KClO3 ----> 2KCl + 3O2 If 5.0 g of KClO3 is decomposted, what volume of O2 is produced at STP? Some help, walkthroughs, pages that explain how to do this exactly... would be great. Needed ASAP!
DV8 2XL Posted May 23, 2006 Posted May 23, 2006 Gee, ya shoulda been listening durring class - these are as basic as it gets. Maybe pick up your textbook and read it?
Renegade Posted May 23, 2006 Author Posted May 23, 2006 We turned it in... and uhm, we didn't really go over this, it's a problem in a packet... We did mole-to-mole, but not these. Anyhow, the class im taking is "Chemistry in the Community" -- It's not Chemistry itself.. so Stoichiometry was not covered in the textbook... And our teacher doesn't generally help us... So yeah.
DV8 2XL Posted May 23, 2006 Posted May 23, 2006 Lucky you, I'm in a good mood tonight. Try: http://www.chemtutor.com/mols.htm Enought there to figure it out on your own.
Renegade Posted May 23, 2006 Author Posted May 23, 2006 Alrighty, thanks! Could you point me in the direction of which section to read? Cause alot of these seem similar.. but... I'm not sure which one I read for each problem. Thx...
DV8 2XL Posted May 23, 2006 Posted May 23, 2006 You've got to be kidding! I threw you a bone and now you want me to go and pick it up for you? You're on your own now kid, don't let the door hit your ass on the way out.
encipher Posted May 23, 2006 Posted May 23, 2006 1) Equation: N2 + 3H2 ---> 2NH3 Problem: What volume of NH3 is produced if 25.0g of N2 is reacted with an excess of H2? Since there is excess H2 then the limiting reactant will be the N2. Therefore the amount of NH3 produced is based on how much N2 gas there is, in this case 25 grams. The calculations begin as follows: How Only at STP can you multiply by 22.43 L/mol. If you are not at STP then you MUST use the formula PV = nRT, Where P is the pressure in atm, V is the volume in Liters, n is the number of moles, R is the constant (.0821 for atm) and T is the temperature in kelvin. Now that I showed you how to do this one, you should be able to do the other.
Borek Posted May 23, 2006 Posted May 23, 2006 Check this out: stoichiometric calculations Best, Borek -- Chemical calculators at www.chembuddy.com equation balancer and stoichiometry calculator www.pH-meter.info
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