bro Posted May 25, 2004 Posted May 25, 2004 I believe that once a star ignites' date=' its gravitational effect is felt immediately (unlike the 8 minutes for light to reach Earth) in the area under its influence and the field of effect is proportional to the size of the star that has ignited. Alas the only way to truly measure this you would have to be close enough to a star's ignition to measure how long before its gravitational effects were felt on any planetary bodies near it.[/quote'] A star's egnition will not affect its gravitational field. It doesn't matter if you got a star, a black hole or randomly floating rocks - the gravitational field will stay the same as long as the center of mass is at the same location. (The loss of mass due to fusion reactions - radiation of that energy in the form of EM waves will cause a VERY slow decrease in gravity, besides, it takes the light years just to reach the surface of the star.) If you take a, standard - type II if I'm not mistaken, supernova - the gravitational field is changed because lots of matter is ejected by the collapsing star, and yet, until you're closer to what remains of the star than that ejected matter, you won't feel the difference.
geistkiesel Posted June 16, 2004 Posted June 16, 2004 First post One doesn't need god to answer any of the issues you discuss. Science has the perfect explanation for it all. Given a huge number of universes, huge, huge number of universes, that one of these universes turns out like ours is to be expected. It goes like this: The odds that the insantaneous direction of all the air molecules in the room are what they are, at this instance, as measured against of all the possibilities of directions they could be, is the same odds that all the air molecules in the room will suddenly, buy chance, move in the direction of the wall in front of you. You can measure this event as there wont be a wall in front of you when it occurs.
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