need help!!!

[Guest Dumass]

hi can anyone here help me solve this???

[wolfson]

What was the question?, if unsure which variable do you want me to relate to??

[Guest Dumass]

i'm from another forum & a member has posted this problem. i have no idea what it is or what it's asking for.

any info. or input will be helpful

[VendingMenace]

hmm...it appears to be as wolfson says. There doesn't really seem to be a question. What forum are you from, if you give us a link to the original post, perhaps that would shed some light on it?

[Dudde]

as I was too hurried to say earlier when I saw this, and these two have just stated, there is no question

 

give a link

 

please

[Guest Dumass]

i copied the problem from the posting..

oh btw it's not from a math/science forum... just a motorcycle forum... some one must have dug into his text book or something

 

http://www.r1-forum.com/forums/showthread.php?s=&threadid=55773&perpage=20&pagenumber=1

[wolfson]

E = sqrt( p^2c^2 + m^2c^4)

 

E=f(m, p))

SR:-

E = sqrt( p^2c^2 + m^2c^4)

if

E=mc^2 (m > 0 & p = 0) and

E=pc (m = 0 & p > 0).

 

Let E = f(m, p), where

f(m,p)

=mc^2 (m > 0 & p = 0)

=pc (m = 0 & p > 0)

= '?' ( m > 0 & p > 0)

E=G^2=c^2

 

m = sqrt(c'/c)*m

 

dimension of mc2 is [ M ][ L ]2/[ T ]2

 

These are preliminary answers I have worked, but I will have to study for a bit longer to contribute L^T.

[wolfson]

I think the idea is that when E >> p the general formula for the energyof a particle with mass m and momentum p.

 

E = (m^2 + p^2)^(1/2)

 

can be approximated by keeping just the first two terms in the

expansion

 

 

E = p + m^2/2p + ...

 

 

If you kept only the leading term in the expansion you would have

E = p,

which corresponds to a particle that travels at the speed of light.