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Posted

can please solve this although looks simple but i can't find my mistake

 

 

An aircraft is flying at height of 3400m above the ground.If the angle subtended at a groung observation point by the aircraft positons 10secs apart is 30degrees ,what is the speed of the aircraft?

 

tan30=10v\3400

 

 

well the ans i got is 196m/sec but actually the answer written is 182m/sec

Posted

I`ve moved this to the maths section for you, you`re more likely to get a faster answer than in the Mechanics section :)

  • 5 months later...
Posted
can please solve this although looks simple but i can't find my mistake

 

 

An aircraft is flying at height of 3400m above the ground.If the angle subtended at a groung observation point by the aircraft positons 10secs apart is 30degrees ,what is the speed of the aircraft?

 

tan30=10v\3400

 

 

well the ans i got is 196m/sec but actually the answer written is 182m/sec

Hint: Consider the equilateral triangle with base=10v, and height=3400. So, half base=5v.

Check that tan(15)=5v/3400, v is in mt/sec, angle in degrees.

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