clarisse Posted November 13, 2006 Posted November 13, 2006 I am really lost with this question... could anyone please point me in the right direction? 2-chloropropanoic acid and 2-hydroxypropanoic acid can both show optical activity. Identify the feature whcih both molecules possess that accounts for this property. When 2-hydroxypropanoic acid is formed from 2-chloropropanoic acid, the product shows no optical avtivity. Deduce the type of nucleophilic substitution that takes place and explain your answer. The first part is ok. I however can't figure out the following part. Working kind of backwards I would think that perhaps it is an Sn2 mechanism because the formation of the carbocation is not favoured because of the C=O bond of the carboxyl group and the H on the other side so the carbocation wouldn't be stabilized? I however can't see how the product isn't optically active. Help please?
clarisse Posted November 24, 2006 Author Posted November 24, 2006 someone? help? please? Ok, I think I know why the resulting substance wouldn't display optical activity: because it would be a recemic mixture... which means that the two enantiomers are being produced in approximately equal proportions. I however don't see how this helps explain the mechanism of the reaction.
psynapse Posted November 24, 2006 Posted November 24, 2006 optical activity.. Does this refer to chiral molecules. If so you might want to try and produce a racimic mixture in the latter reaction.
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