aommaster Posted December 24, 2003 Share Posted December 24, 2003 What properties would be different (other than the structure itself) of let's say, propan-1-ol and propan-2-ol? Link to comment Share on other sites More sharing options...
wolfson Posted December 30, 2003 Share Posted December 30, 2003 Well the two alcohol's that you just gave are positional isomers, this is where a substituent occupies different positions on the carbon chain. The boiling point of Pro 1 is 370K, and pro 2 is 355K, the boiling points (and other physical properties) of the two compounds are different. Although the chemical properties are the same, the reactivities will be different due to the different envirenments of the OH group. Link to comment Share on other sites More sharing options...
aommaster Posted December 30, 2003 Author Share Posted December 30, 2003 oh, ok. Thanx man Link to comment Share on other sites More sharing options...
apathy Posted May 30, 2004 Share Posted May 30, 2004 What properties would be different (other than the structure itself) of let's say, propan-1-ol and propan-2-ol? the dipole moment Link to comment Share on other sites More sharing options...
aommaster Posted May 30, 2004 Author Share Posted May 30, 2004 Could you please explain further? Link to comment Share on other sites More sharing options...
JustinM.Dragna Posted June 2, 2004 Share Posted June 2, 2004 This is an odd question. I wouldn't expect any great difference between them. The different boiling point is one. There would probably be a small difference in the acidity of the hydrogen on the oxygen too. I think you could account for that by the difference in the dipole moment. 1-prop would probably be a little bit more acidic than 2-prop because the extra methly group next to the carbon with the hydroxyl group(what's that carbon called? alpha or beta?) on it destabilizes the conjugate base by "pushing" electrons onto the already negatively charged oxygen atom through sigma bonds. Of course it's not that much of a difference considering that 1-prop has an ethyl group donating electrons as well, but then there isn't that much of a difference between the two compounds. Another difference would be that 2-prop has more symmetry elements than 1-prop. For instance 2-propanol has an obvious sigma or mirror plane. This would make the NMR spectra for them differ a good deal. I can't really think of too much more to say, but i feel like i gave a pretty good rant. I hope this helps you out. Link to comment Share on other sites More sharing options...
aommaster Posted June 2, 2004 Author Share Posted June 2, 2004 Thanx! What is meant by the dipole moment? Acidity? Link to comment Share on other sites More sharing options...
Skye Posted June 2, 2004 Share Posted June 2, 2004 The dipole moment is the difference in charge across a molecule, or across a bond. If you have a C-OH bond, the OH group is slightly more negatively charged and the C is slightly more positively charged. The difference between the two charges as a function of the distance is the dipole moment. With the 1- or 2-propanol, the two molecules have the OH in a different position, so the distance the difference in charge occurs over, averaged over the whole molecule, will be different. In the 1-propanol, these distances are larger, as the OH is at the end of the molecule, and so the dipole moment will be larger. Link to comment Share on other sites More sharing options...
aommaster Posted June 2, 2004 Author Share Posted June 2, 2004 oh, ok. Thanx for clarifying that to me! Link to comment Share on other sites More sharing options...
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