Primarygun Posted December 31, 2006 Share Posted December 31, 2006 In a simple harmonic motion, the tension is greater than the component of weight along the rope by mv^2/r right? Link to comment Share on other sites More sharing options...
EvoN1020v Posted December 31, 2006 Share Posted December 31, 2006 If you are swinging the rope vertically, then the pendulum at the bottom has the greatest tension. ([math]Tension = ma + Fg[/math]). (Note: In circular motions, [math]F=ma[/math] always is [math]F=\frac{mv^2}{r}[/math]). If you are swinging the rope horizontally, the tension is equally all way around. Link to comment Share on other sites More sharing options...
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