Primarygun Posted December 31, 2006 Posted December 31, 2006 In a simple harmonic motion, the tension is greater than the component of weight along the rope by mv^2/r right?
EvoN1020v Posted December 31, 2006 Posted December 31, 2006 If you are swinging the rope vertically, then the pendulum at the bottom has the greatest tension. ([math]Tension = ma + Fg[/math]). (Note: In circular motions, [math]F=ma[/math] always is [math]F=\frac{mv^2}{r}[/math]). If you are swinging the rope horizontally, the tension is equally all way around.
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