BeAnBeAn Posted January 9, 2007 Posted January 9, 2007 In order for a moving bowling ball and a moving Ping-Pong ball to have the same momentum what must happen to the speed of both-balls? And what would happen to the speed not mass.
Bluenoise Posted January 9, 2007 Posted January 9, 2007 Well that depends on how fast they are moving to begin with. That peice of information, plus this equation is all you'll need. (plus the assumption that a bowling ball is far more massive then a pingpong ball.) momentum = velocity x mass.
BeAnBeAn Posted January 9, 2007 Author Posted January 9, 2007 well lets just say its going 5m per second? so then it the two balls would have to be lighter? but im asking about what needs to happen with the speed
chemhelper Posted January 9, 2007 Posted January 9, 2007 Obviously, the bowling ball will have a larger mass than the ping pong ball. Presuming the two are moving at the same speed initially, two things could happen to make the momentum the same: 1. The bowling ball would have to slow down 2. The ping pong ball would have to speed up just remember, as was stated, p=m*v ---- Have homework questions in chemistry, physics or math? Who Likes Homework -- http://www.wholikeshomework.com
Bluenoise Posted January 9, 2007 Posted January 9, 2007 Basically the speed of the ping-pong ball would have to equal the speed of the bowling ball times the ratio of their masses. i.e. speed of ping-pong ball = speed of bowling ball x ( weight of bowling ball / weight of ping-pong ball.)
Rocket Man Posted January 13, 2007 Posted January 13, 2007 is this an a vacuum or can we also talk about the mass of air being dragged behind the objects? (get a super-cray to do the number crunching)
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