Lowemack Posted January 30, 2007 Posted January 30, 2007 (sorry posted this first in Quantum mechanics by mistake:confused: ) Does anybody know what the formula is for the graph you see in text books, of speed against time for a constant force applied to an object. The one where speed increases with time, and then levels of as it approaches C. For non reletavistic speeds I think the formula is f=ma, which when re-arranged would give t=mv/f. and for a force of 1N applied to a mass of 1kg t=v. So after 10 seconds the mass would be doing 10m/s,after 20s 20m/s. But at speeds close to C we know that this is not the case, so does anybody know the formula that matches the graph I mentioned?
Meir Achuz Posted February 28, 2007 Posted February 28, 2007 [tex]v=at/\sqrt{1+a^2t^2}[/tex] for an object with a constant acceleration a in its rest frame.
TriggerGrinn Posted February 28, 2007 Posted February 28, 2007 [tex]v=at/\sqrt{1+a^2t^2}[/tex] for an object with a constant acceleration a in its rest frame. they use (math) (/math) here with [math] brackets [\math] so you said: [math]v=at/\sqrt{1+a^2t^2}[/math]
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now