tukeywilliam Posted March 19, 2007 Posted March 19, 2007 For a vertical spring, if we let x_s be the total extension of the spring from its equilibrium position without a hanging object, then why does x_s = -\left(\frac{mg}{k}\right) + x ? Is this saying that the extension of the spring is changed for a vertical spring when a weight is added on? Does it follow from: -kx = mg x = -\left(\frac{mg}{k}\right) ? Why is there a +x in the x_s expression? Thanks
Klaynos Posted March 19, 2007 Posted March 19, 2007 I can't remember the equations or definitions off hand atm. But from what I recall, isn't that x just the initial displacement when the spring is at rest?
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