beatulec Posted April 7, 2007 Share Posted April 7, 2007 I was wondering if someone could help me out with these two equations, somehow I cannot manage to balance them properly... 1)CrO4^2- + Fe^2+ --> Cr^3+ + Fe^3+ (in acidic solution) 2)MnO4^- + ClO2^- --> MnO2 + ClO4^- (in basic solution) I'll really appreciate any help, Thanks! Link to comment Share on other sites More sharing options...
Comandante Posted April 7, 2007 Share Posted April 7, 2007 What happend with oxygen in that first equation, it didn't disappear into the thin air did it? By the way this question goes into homework help section. Link to comment Share on other sites More sharing options...
woelen Posted April 7, 2007 Share Posted April 7, 2007 Write down half reactions (e.g. CrO4(2-) + 8H(+) + 3e --> Cr(3+) + 4H2O) for all of the oxidizers and for the reductors, and then combine the oxidizer equation and reductor equation, such that the number of electrons is the same at both sides of the arrow. Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now