Afi Posted April 21, 2007 Posted April 21, 2007 An exercise I have problems with: In a thermos bottle with heat capacity 90 J/K there is 0.4 kg water. The temperature of the water and the thermos bottle is 313 K. Brass with mass 0.1 kg has temperature 363 K and specific heat capacity 380 J/(kg *K). It is dropped into the thermos bottle. a) What will the temperature of the water be? b) 0.02 kg ice with temperature 273 K is added. What will the temperature of the water be now? I presume that no heat will leak from the thermos bottle. I think I will manage a), but b) is more difficult. Help will be appreciated.
swansont Posted April 21, 2007 Posted April 21, 2007 Show your work. Part b requires you account for the phase change in the ice, by using latent heat.
Afi Posted April 21, 2007 Author Posted April 21, 2007 I will try on part b. Can this be correct? q*m is the energy needed to melt ice C is heat capacity c is spcific heat capacity m=mass T=temperature i=ice w=water t=thermos bottle b=brass
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