someguy Posted July 15, 2007 Posted July 15, 2007 I have no clue what the formula is for calculating this is but i'm sure some of you guys could do this without too much trouble if i'm not screwing something it up and it is possible at all. suppose you had a rest mass of 5kg and knowing that as velocity increases so does mass what velocity (in a straight line) would be required for the mass to increase to a total of 100kg. when i think about it it seems like the rate of acceleration is important but i'm not totally sure. if it is, then it is fair to say that speed actually has nothing to do with it and in fact acceleration is the only defining factor in calculating the final mass right? and if this is right then two objects of equal rest mass could be accelerated to another equal speed but accelerated at different rates and they would end up having different masses? if that is right then rest mass sort of loses some meaning to me because both the old and new masses would technically still be rest masses since you can only compare rest or not in relation to each other. unless rest mass implies to suppose the two objects at rest mass are not only stationary in relation to each other but actually occupy the same space at the same time that way you could never have two different rest masses like my example earlier.. but that just seems wrong. if that was just right (the only that matters is rate of acceleration), then if you had a mass of 5kg and an acceleration rate of n-->0 how fast could you go without using more than 28500000000kj of energy?
timo Posted July 15, 2007 Posted July 15, 2007 [math] E(v) = m(v) c^2 = \frac{m(v=0) c^2}{\sqrt{1- v^2/c^2}}[/math]. No acceleration there, only velocity(v).
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