dstebbins Posted August 24, 2007 Posted August 24, 2007 According to the laws of Relativity, matter and energy are equivalent and interchangable at the rate of e=mc^2. This means that as an object speeds up, thus increasing its kinetic energy, its mass also increases. If a 1kg object is stationary, it has a mass of exactly 1kg. However, if it is going at a [relative] speed of 2 m/s, then by the rule of e=.5mv^2, it has one joule of energy, and by the rule of e=mc^2, it thus has an extra 1/c^2 of mass. Not enough to worry about, but once you get to a velocity of c, the mass becomes infinite. Wait: Mass becomes infinite?! What's Einstein's mathematical justification for that? Mathematically, infinity occurs when you divide by zero (e.g. a vertical line has an infinite slope because it's x rise over zero run, or at least so says my Math professor, from freakin' CHINA!); the only reason high school students are taught that you can't divide by zero is because it's more practical to say that for high school purposes, so where do you divide by zero here? I'm not saying Einstein's wrong. Quite the opposite: I'm interested in understanding his point of view. My IQ is only 20 points under his, not to mention I have the same type of autism he had, so I feel I have a good shot and understanding this.
BenTheMan Posted August 24, 2007 Posted August 24, 2007 The mass becomes infinite because the Lorentz transform of mass has a 1-v^2/c^2 in the denominator. So you are dividing by zero. My IQ is only 20 points under his, not to mention I have the same type of autism he had, so I feel I have a good shot and understanding this. What does this have to do with anyhting?
Reaper Posted August 24, 2007 Posted August 24, 2007 I'm not saying Einstein's wrong. Quite the opposite: I'm interested in understanding his point of view. My IQ is only 20 points under his, not to mention I have the same type of autism he had, so I feel I have a good shot and understanding this. That's pure speculation, and off topic. But you are free to discuss your speculations in the speculations sub-forum. Anyways, to expand on what Bentheman said, the equations for the Lorentz transformation are: t' = y [t - (vx/c^2)] x' = y (x - vt) Y' = Y z' = z And "y" (just the lower case; its actually some greek symbol I forgot the name to) is the Lorentz Factor. y = 1 / [ 1 - (v^2 / c^2)] Take note that these equations are describing what is happening in 4 dimensional spacetime, so you need 4 points to describe them. <edit> Relativistic mass: m = y m(initial) where, as before, y = 1 / [ 1 - (v^2 / c^2)]^ 1/2 When v = c, the denominator is zero, and thats why mass goes to infinity as one approaches the speed of light.
foodchain Posted August 24, 2007 Posted August 24, 2007 That's pure speculation, and off topic. But you are free to discuss your speculations in the speculations sub-forum. Anyways, to expand on what Bentheman said, the equations for the Lorentz transformation are: t' = y [t - (vx/c^2)] x' = y (x - vt) Y' = Y z' = z And "y" (just the lower case; its actually some greek symbol I forgot the name to) is the Lorentz Factor. y = 1 / [ 1 - (v^2 / c^2)] Take note that these equations are describing what is happening in 4 dimensional spacetime, so you need 4 points to describe them. <edit> Relativistic mass: m = y m(initial) where, as before, y = 1 / [ 1 - (v^2 / c^2)]^ 1/2 When v = c, the denominator is zero, and thats why mass goes to infinity as one approaches the speed of light. Why does a photon have no mass then?
Quartile Posted August 24, 2007 Posted August 24, 2007 It has zero rest mass, but its always moving at the speed of light. Is that right?
swansont Posted August 24, 2007 Posted August 24, 2007 If a 1kg object is stationary, it has a mass of exactly 1kg. However, if it is going at a [relative] speed of 2 m/s, then by the rule of e=.5mv^2, it has one joule of energy Well, 2 Joules actually (.5 * 22) Why does a photon have no mass then? The photon travels at c, and can't have rest mass if it does. The actual equation is E2=p2c2 + m02c4 m0 is the rest mass, so we can see that the photon still has momentum It has zero rest mass, but its always moving at the speed of light. Is that right? Yes
dstebbins Posted August 24, 2007 Author Posted August 24, 2007 So what do these variables stand for, and why do we prime them?
swansont Posted August 25, 2007 Posted August 25, 2007 x, y and z are the cartesian coordinates in one frame. The primed values are in the other frame.
Sisyphus Posted August 25, 2007 Posted August 25, 2007 My IQ is only 20 points under his, not to mention I have the same type of autism he had, so I feel I have a good shot and understanding this. There are at least five things wrong with that sentence.
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now