smarty_pants Posted August 24, 2007 Posted August 24, 2007 Each letter represnts a different digit.Given GOD=605 what number does MOVED STAND FOR? A D A M + A N D + E V E = M O V E D
Fuzzwood Posted August 24, 2007 Posted August 24, 2007 Can I presume G=6, O=0, and D=5 Or is it a multiplication of GOD which makes 605?
Pre4edgc Posted August 24, 2007 Posted August 24, 2007 It's the first one. The entire thing is addition, so using multiplication in an example is kind of pointless.
cjohnso0 Posted August 27, 2007 Posted August 27, 2007 Well, I think this works, double check em if ya like. [hide] A=8 D=5 E=9 M=1 N=7 O=0 V=3 ADAM=8581 AND=875 EVE=939 MOVED=10395 Got it by the given GOD and fiddling with the #'s [/hide]
Pre4edgc Posted August 27, 2007 Posted August 27, 2007 That looks good. Great job! I was trying to do the same thing, but I kept getting the numbers wrong. I did get the 1 and 9 right though.
someguy Posted August 28, 2007 Posted August 28, 2007 I got the same answers, this is how i did it. [hide] M+5+E= *5 A+N+V+*=()E 5+A+E+()="V A+"=M0 let's assume that all letters are integers from 0-9 let's also assume you can't use the same letter twice. therefore A+" must = 10 therefore M=1 1+5+E= *5 -> 6+E=*5 * must be one and E must be 9 if statement 1 is true A+N+V+1=()9 ANV must be 378 not necessarily in that order. (only numbers left that can give that sum if statement 1 and 2 were correct.) ()= 1 5+A+9+1="V V=[3,7 or 8] 15+A = "[3,7 or 8] A=8 " = 2 V=3 [/hide]
uncool Posted August 30, 2007 Posted August 30, 2007 The way I did it: [hide]M must be 1, as it is an extra place out. Then M + D + E = D, so M + E is 0, so E is 9. Then, A must be 8, as that is the only one that will give the 1 for M. D + A + E + carry(A + N + V) = V + 20. A + N + V + 1 = E + 10*carry, so 9 + N + V = 9 + 10*carry, so N + V = 10, and the carry is 1. 9 + 8 + 5 + 1 = V + 20, so V = 3, and N = 7. O = 0 M = 1 V = 3 D = 5 G = 6 N = 7 A = 8 E = 9 MOVED = 10395. [/hide] =Uncool-
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