anthropos Posted September 2, 2007 Share Posted September 2, 2007 By using hot acidified potassium manganate (VII), is one of the products of the strong oxidation of hex-3-en-1-ol (leaf alcohol) this compound? Is it a diol or acid or both? What is the IUPAC name? Link to comment Share on other sites More sharing options...
John Cuthber Posted September 2, 2007 Share Posted September 2, 2007 It's 3 hydroxy propanoic acid, but I also think it's the wrong answer. What do you know about alcohols and permanganate? Link to comment Share on other sites More sharing options...
Margel Posted May 27, 2009 Share Posted May 27, 2009 KMnO4 can cleave the double bond so 3-hydroxypropanoic acid (IUPAC name) is one of the possible products. KMnO4 is a very strong oxidizing agent and this is why chemists usually used milder oxidizing agents such as Jones reagent, PCC, PDC etc. . 3-hexenoic acid is the major product if the oxidant will not cleave the double bond. The structure you have drawn is a carboxylic acid. No, it is not a diol. Link to comment Share on other sites More sharing options...
UC Posted May 27, 2009 Share Posted May 27, 2009 The thing about permanganate is that is cleaves double bonds and completely oxidizes any functional groups that it can. You have the wrong reaction product there. As was already said, 3-hydroxypropanoic acid is the correct name. You could call this a beta-hydroxy acid, the simplest possible one, in fact. Link to comment Share on other sites More sharing options...
hermanntrude Posted May 27, 2009 Share Posted May 27, 2009 KMnO4 can cleave the double bond so 3-hydroxypropanoic acid (IUPAC name) is one of the possible products. KMnO4 is a very strong oxidizing agent and this is why chemists usually used milder oxidizing agents such as Jones reagent, PCC, PDC etc. . 3-hexenoic acid is the major product if the oxidant will not cleave the double bond. The structure you have drawn is a carboxylic acid. No, it is not a diol. Margel, please read the policy concerning homework help. We don't just give answers outright. Link to comment Share on other sites More sharing options...
John Cuthber Posted May 27, 2009 Share Posted May 27, 2009 Margel, don't just read that policy; read the dates too. I wonder if the guy who asked the question a couple of years ago is still studying chemistry. Link to comment Share on other sites More sharing options...
hermanntrude Posted May 27, 2009 Share Posted May 27, 2009 hehehe i didn't spot that Link to comment Share on other sites More sharing options...
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