gonelli Posted September 9, 2007 Share Posted September 9, 2007 This is a idea that came to me when my math teacher was stressing the point that we need to write that the sqaure root of 25 is 5 and -5, and that we must include that even when that answer can only be positive. So i was think that having the sqaure root of a number like 25 in an equation for a line would result in essentail two different lines. I don't really know if you're allowed to do something like that. For example: x^2 + 2x + 25^(1/2) So that could be either + 5 or - 5 as a constant, right? Please let me know if this makes any sense. Link to comment Share on other sites More sharing options...
the tree Posted September 9, 2007 Share Posted September 9, 2007 Not really, [math]\sqrt{25}=5[/math] and that's it. "Square root", being a well defined function has only one output per input. Its relationships like [math]x^{2}=25[/math] that have two solutions, namely [math]x=\pm 5[/math]. Link to comment Share on other sites More sharing options...
Country Boy Posted September 9, 2007 Share Posted September 9, 2007 This is a idea that came to me when my math teacher was stressing the point that we need to write that the sqaure root of 25 is 5 and -5, and that we must include that even when that answer can only be positive. I hope your teacher DIDN'T say precisely that! [math]\sqrt{25}= 5[/math], not -5. What is true is that the equation, [math]x^2= a[/math] has TWO solutions. One is [math]\sqrt{a}[/math], the other is [math]-\sqrt{a}[/math]. The reason we need to write the "-" (or sometimes [math]\pm[/math]) is BECAUSE [math]\sqrt{a}[/math] does NOT include the negative. You might then, on the basis of other information (whether a negative number is physically possible if it is a physic problem, the fact that "distance" is always positive) decide that one of those solutions does not actually work in that particular problem. So i was think that having the sqaure root of a number like 25 in an equation for a line would result in essentail two different lines. I don't really know if you're allowed to do something like that. For example: x^2 + 2x + 25^(1/2) So that could be either + 5 or - 5 as a constant, right? Please let me know if this makes any sense. No. [math]25^{\frac{1}{2}}[/math] or [math]\sqrt{25}[/math] are defined as POSITIVE 5. In general, for any positive number, a, [math]a^{\frac{1}{2}}[/math] or [math]\sqrt{a}[/math] are defined as the POSITIVE number whose square is a. Link to comment Share on other sites More sharing options...
gonelli Posted September 11, 2007 Author Share Posted September 11, 2007 Ahhh, that makes sense. And by the way, my teacher was actually refering to a question where it came down to x^2 = 25, so I now see how it works. Thanks! Link to comment Share on other sites More sharing options...
the tree Posted September 11, 2007 Share Posted September 11, 2007 Quadratics, which are equations like that that have no higher power than 2 (in general: [math]ax^2 + bx + c = 0[/math]) always have two solutions. In some cases the two solutions will be the same, in some cases different, and in some not real. (the last is for a later date) Link to comment Share on other sites More sharing options...
Country Boy Posted September 14, 2007 Share Posted September 14, 2007 Quadratics, which are equations like that that have no higher power than 2 (in general: [math]ax^2 + bx + c = 0[/math]) always have two solutions. In some cases the two solutions will be the same, in some cases different, and in some not real. (the last is for a later date) I would say that a quadratic equation is an equation whose highest power IS 2 (not "no higher than 2- that would include linear equations.). Link to comment Share on other sites More sharing options...
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