MrSandman Posted October 11, 2007 Posted October 11, 2007 +-/x +/-x x-/+ x/-+ -/x+ /-x+ -/+x /-+x /x+- -x+/ /+x- -+x/ x+-/ x+/- +x-/ +x/- Here's the possible solutions
MrSandman Posted October 11, 2007 Posted October 11, 2007 Crap, then it's a trick question. Try using it again and where it says x use x as a variable.
MrSandman Posted October 11, 2007 Posted October 11, 2007 You use X instead of "times" a variable like in. 3x-2=22 solution: x=8
the tree Posted October 11, 2007 Posted October 11, 2007 For what it's worth, there are 24 possible permutations, not 16. Although I wouldn't put too much stock by the brute force approach anyway. Assuming it's a trick question the moment you run into difficulty isn't definitely not a good approach to any problem.
Variant Posted November 18, 2007 Posted November 18, 2007 For what it's worth, there are 24 possible permutations, not 16. Although I wouldn't put too much stock by the brute force approach anyway. Assuming it's a trick question the moment you run into difficulty isn't definitely not a good approach to any problem. Ahh, but it IS a trick question. Due to the nature of the way the symbols work, you only need to look at four possibilities to eliminate them all. (3-3) = 0, you'll get nowhere with that. (3/3) = 1, can't get very far with a 1 either. (3x3) = 9, you used your multiply, you have one add to use and it's downhill from there. (3+3) = 6, used your add already, 3 x 6 = 18, downhill from there. You simply can't get a high enough number with any of them for the rest to work, you will always end up with a smaller number if you continue the problem. But if you use x as a variable, this is possible: (3 + 3)x3 - 3 / 3 = 29, where x = 5 6*5*3 = 90 90 - 3 = 87 87 / 3 = 29
ishmael Posted November 18, 2007 Posted November 18, 2007 Do all of the symbols have to be used? Can you use ! (factorial)? Or exponents - e.g. 3 to third power is 27?
ydoaPs Posted November 18, 2007 Posted November 18, 2007 (3 + 3)x3 - 3 / 3 = 29, where x = 5 I'm not getting five. Order of Operations(Please Excuse My Dear Aunt Sally). Parenthesis (3+3)x3-3/3=29 becomes 6x3-3/3=29 Exponents There are no exponents, so we move to the next step. Multiplication 6x3-3/3=29 becomes 18x-3/3=29 Division 18x-3/3=29 becomes 18x-1=29 Addition 18x-1=29 becomes 18x=30 Now, solve for x. 18x=30 becomes x=18/30 Reduce your answer. x=18/30 becomes x=3/5
Variant Posted November 18, 2007 Posted November 18, 2007 I'm not getting five. Order of Operations(Please Excuse My Dear Aunt Sally).Parenthesis (3+3)x3-3/3=29 becomes 6x3-3/3=29 Exponents There are no exponents, so we move to the next step. Multiplication 6x3-3/3=29 becomes 18x-3/3=29 Division 18x-3/3=29 becomes 18x-1=29 Addition 18x-1=29 becomes 18x=30 Now, solve for x. 18x=30 becomes x=18/30 Reduce your answer. x=18/30 becomes x=3/5 (3+3)x3-3/3=29 becomes 6x3-3/3=29 I meant this to be 6*5*3-3/3=29 not 6*5*3-(3/3)=29 18x-3/3=29 But I don't know where this comes from: 18x-3/3=29 becomes 18x-1=29 6*5 = 30 30*3 = 90 90 - 3 = 87 87 / 3 = 29 nevermind, I see you said order of operations. I guess it can't work that way.
ydoaPs Posted November 18, 2007 Posted November 18, 2007 I meant this to be 6*5*3-3/3=29 not 6*5*3-(3/3)=2918x-3/3=29 Following standard hierarchy, 6*5*3-3/3=6*5*3-(3/3) NOT (6*5*3-3)/3 But I don't know where this comes from:18x-3/3=29 becomes 18x-1=29 It's standard order of operations. Just like you learned in school.
Variant Posted November 18, 2007 Posted November 18, 2007 Following standard hierarchy, 6*5*3-3/3=6*5*3-(3/3) NOT (6*5*3-3)/3 It's standard order of operations. Just like you learned in school. Yeah, I went back and edited my post. So I guess there is no solution within the rules. I'm not satisfied saying that... so here goes more wasted paper...
ydoaPs Posted November 18, 2007 Posted November 18, 2007 So I guess there is no solution within the rules. Don't be so sure. given (3?3)?3?3?3=29using + - / x only once Answer: [hide]x=-3[/hide] Explanation: [hide]Using x as a variable: (3+3)/3-3x3=29 Parenthesis (6)/3-3x3=29 Exponents(N/A) Multiplication(and Division from left to right) (6)/3-3x3=29 becomes 2-9x=29 Now, we solve for x. Getting all terms containing the x variable to one side via addition and subtraction yields -9x=27. Dividing both sides by the coefficient of x yields x=-3.[/hide]
Variant Posted November 18, 2007 Posted November 18, 2007 Don't be so sure. Answer: [hide]x=-3[/hide] Explanation: [hide]Using x as a variable: (3+3)/3-3x3=29 Parenthesis (6)/3-3x3=29 Exponents(N/A) Multiplication(and Division from left to right) (6)/3-3x3=29 becomes 2-9x=29 Now, we solve for x. Getting all terms containing the x variable to one side via addition and subtraction yields -9x=27. Dividing both sides by the coefficient of x yields x=-3.[/hide] Oh wow... I never even considered putting something like what you did for x. I'm DUH! Heh. Also can't believe I forgot order of operations... shows how much 20 year old math I actually have to use (a.k.a NONE)
ydoaPs Posted November 18, 2007 Posted November 18, 2007 That's just the first answer I came up with. There may be others. I just trial&errored for a few minutes and that just happened to be the first one I reached.
Variant Posted November 20, 2007 Posted November 20, 2007 Or, x = 3: (3x3) + 3 - 3/3 = 29 Wow, I'm dumb. I'd considered doing exactly that and found it wrong... but I must have just DID it wrong lol. Probably because of order of operations... again.
the tree Posted November 20, 2007 Posted November 20, 2007 [math](3 \times 3)+3-33\neq 29[/math] Because I'm clever.
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