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Ksp's and Ka's...help please

Guest prvbspike
Guest prvbspike
in Applied Chemistry

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If i have the Ksp of sodium benzoate(a sald of the WA benzoic acid), how do i find the Ka of benzoic acid?

As an example:

 

CH3COOH(aq) + H2O(l) <> H3O+(aq) + CH3CO2-(aq)

 

Ka = [H3O+][CH3CO2-] / [CH3COOH]

 

as for Ksp:

 

MmXx(s) <> mMn+(aq) + xXy-(aq)

 

Ksp = [Mn+]m[Xy-]x

 

You need to transpose the Ksp as laid out to formulate the Ka, you should have all values.

 

You should get a value of 6.28e-5.

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