Guest prvbspike Posted February 23, 2004 Posted February 23, 2004 If i have the Ksp of sodium benzoate(a sald of the WA benzoic acid), how do i find the Ka of benzoic acid?
wolfson Posted February 23, 2004 Posted February 23, 2004 As an example: CH3COOH(aq) + H2O(l) <> H3O+(aq) + CH3CO2-(aq) Ka = [H3O+][CH3CO2-] / [CH3COOH] as for Ksp: MmXx(s) <> mMn+(aq) + xXy-(aq) Ksp = [Mn+]m[Xy-]x You need to transpose the Ksp as laid out to formulate the Ka, you should have all values. You should get a value of 6.28e-5.
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