mbeychok Posted October 24, 2007 Posted October 24, 2007 Calculating the viscosity of a blended liquid consisting of two or more liquids having different viscosities is a three step procedure. The first step involves calculation of the Viscosity Blending Index (VBI) of each component of the blend using the following equation (known as a Refutas equation): (1) VBI = 14.534 × ln[ln(v + 0.8)] + 10.975 where v is the viscosity in centistokes and ln is the natural logarithm (Loge). The second step involves using this blending equation: (2) VBIBlend = [wA × VBIA] + [wB × VBIB] + ... + [wX × VBIX] where w is the weight fraction (i.e., % ÷ 100) of each component of the blend. In using the above blending equation, it is necessary that all viscosities are determined at the same temperature, for example, 100 oC. The third and final step is to determine the viscosity of the blend by using the invert of equation (1): (3) v = ee(VBI - 10.975) ÷ 14.534 − 0.8 where VBI is the Viscosity Blending Index of the blend and e is the transcendental number 2.71828, also known as [[Euler's number]].
John Cuthber Posted October 27, 2007 Posted October 27, 2007 This version is no more interesting or correct that this one. http://www.scienceforums.net/forum/showthread.php?t=29183
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