Jacques Posted November 8, 2007 Posted November 8, 2007 My question is simple, but I can't find an answer with google or wiki:( How does Plank found that value ? [math]h=6.6*10^{-34} J s[/math] How did he derived it ? Thanks
swansont Posted November 8, 2007 Posted November 8, 2007 It was/is experimentally determined, not derived. http://www.physics.umd.edu/lecdem/services/demos/demosp2/p2-01.htm http://www.aip.org/pnu/1998/split/pnu391-2.htm
Jacques Posted November 22, 2007 Author Posted November 22, 2007 Thanks for the links. I can read that h is the slope of the stopping potential as a function of frequency, mutiplied by the electron charge. h=e(V2-V1)/(f2-f1) Why does the electron charge putted in the equation ? I tried to check if this expression give the good unit of measure. The unit of V is m2·kg·s-3·A-1 The unit of f is s-1 The unit of e is s·A so the unit of h is m2·kg·s-1 The unit of J is m2·kg·s-2 So the unit of h is J·s or m2·kg·s-1 which is consitent I was surprise to see that ampere (A) was a SI base units. I was expecting something more fundamental like the Coulomb © and that A would be a derived unit C·s-1
swansont Posted November 23, 2007 Posted November 23, 2007 Thanks for the links. I can read that h is the slope of the stopping potential as a function of frequency, mutiplied by the electron charge. h=e(V2-V1)/(f2-f1) Why does the electron charge putted in the equation ? Because qV gives you the energy of the electron accelerated through a potential.
Fred56 Posted November 24, 2007 Posted November 24, 2007 It's a proportionality between two measurable aspects, but which two... (angular) momentum; wavenumber; frequency; spin; charge? What dimensionality (units)?
bombus Posted January 20, 2008 Posted January 20, 2008 The plank constant is the size of pixels in the simulation that we inhabit!
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