jeheron Posted November 11, 2007 Posted November 11, 2007 I recently attended a popular science lecture at the University of Sydney. The speaker said that if, given enough time, you travelled in a straight line out into space, you would eventually arrive back where you started from as if space was circular and you had circumnavigated it. Is this remotely correct?
ajb Posted November 11, 2007 Posted November 11, 2007 This is true if the universe is compact and without a boundary. Much like the sphere. Such notions about the topology of the universe are still open.
Martin Posted November 11, 2007 Posted November 11, 2007 I recently attended a popular science lecture at the University of Sydney. The speaker said that if, given enough time, you travelled in a straight line out into space, you would eventually arrive back where you started from as if space was circular and you had circumnavigated it. Is this remotely correct? What ajb says is correct. The universe could be spatially infinite, so that you might travel in a straight line forever and never get back to starting point. or it could have a finite spatial volume which means (since one normally assumes no boundary) that it has to be roughly analogous to the 2D world of a sphere, more or less. interestingly enough, for several years evidence has been accumulating on the side of the latter alternative----what your speaker was talking about the key number is called Omega and it is a measurable density ratio. if Omega is greater than 1, like say 1.01 then the universe is spatial finite, analogous to the surface of a ball (but nothing inside or outside, just the surface itself) if Omega is exactly 0, then it is spatial infinite. like a flat 2D surface extending out indefinitely (but nothing above or below it, just the surface) these are 2D analogies for a 3D space Recently when Omega has been measured with the latest most complete data, there is still some uncertainty but they are getting numbers like 1.011 A paper came out in January 2007 with 1.011 as the "best fit". However it is still not sure enough to say one way or the other. might be infinite volume, might be finite volume in either case boundaryless----no "edge" sometimes people get the notion that because a volume is finite it has to have a boundary but this is not true
ydoaPs Posted November 11, 2007 Posted November 11, 2007 if Omega is greater than 1, like say 1.01 then the universe is spatial finite, analogous to the surface of a ball (but nothing inside or outside, just the surface itself) if Omega is exactly 0, then it is spatial infinite. like a flat 2D surface extending out indefinitely (but nothing above or below it, just the surface) What if [math]0<{\Omega}<1[/math]?
insane_alien Posted November 11, 2007 Posted November 11, 2007 i think martin meant omega = to 1 rather than 0 if omega is less than one it corresponds to negative curvature(whatever that means)
Martin Posted November 12, 2007 Posted November 12, 2007 i think martin meant omega = to 1 rather than 0 if omega is less than one it corresponds to negative curvature(whatever that means) I sure did mean that! thanks alien. Typo. Should have typed if Omega is exactly 1, then it is spatial infinite. like a flat 2D surface extending out indefinitely (but nothing above or below it, just the surface)
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