Jump to content

Recommended Posts

Posted

Hi, I was curious.

 

In chemistry class we did a lab involving an aqueous solution of hydrogen peroxide being catalyzed with potassium iodide to decompose. The solution turned yellow. Why is that?

Posted

The KI is not *catalyzing* the decomposition of the H2O2. It is being oxidized to yield I2, which is the source of the brown color. This reaction is a stoichiometric redox and it is the basis for most quantitative redox titrations (usually using starch as an indicator).

 

Catalytic decomposition of peroxide can be seen with enzymes (see catalase) or metals (Fe, Mn, W). Here, a small trace of the catalyst will, over time eventually lead to the near complete exhaustion of the peroxide (decisively non-stoichiometric).

 

For example, peroxide plus Mn yields oxidized Mn and O2 (sometimes quite vigorously); Fe2+ yields -OH, .OH and Fe3+, and W is used in the titrimetric assay for H2O2.

 

Cheers,

 

O3

Posted
The KI is not *catalyzing* the decomposition of the H2O2. It is being oxidized to yield I2, which is the source of the brown color.

 

If it yields I2, can the Iodine be separated from the solution through evaporation ?

 

Ken

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.