Ammonia

[2nd]

Is it possible to obtaining by this method:

 

2NH3 + NaOH ---> NH4OH + Na

[insane_alien]

wait, you want to make ammonia(i assume from the thread title) but you want to make it by starting off with ammonia and turning it into something different?

 

what?

 

i really can't make sense of this. what exactly is it that you want to do?

[YT2095]

your reaction would only hold true as Ions, you wouldn`t get sodium Metal though, in reality you would likely end up with sodium amide at best, and at worst just a mixture of the 2 you started with.

 

and btw, it`s not Balanced properly either (where would the extra N go for instance?)

[2nd]

Sorry i mean Ammonia Hydroxide

 

your reaction would only hold true as Ions, you wouldn`t get sodium Metal though

Can i separate it away from Ammonia Hydroxide ?

[YT2095]

nope, not really

[Fable]

2NH3 + NaOH ---> NH4OH + Na would really not work. not just because of the nature of the Na. However this would be alittle closer to the truth, but... NH4NO3 + NaOH <---> NH4OH + NaNO3 . I guess that should be correct if possible, i cant back it up yet.

[DrDNA]

you started with ammonia and you want to make ammonia.....hmmmm.....what?????

 

as far as ammonium hydroxide goes, ammonia in water generates ammonium hydroxide

[YT2095]

Fable, yup ammonium nitrate and sodium hydroxide will indeed make Ammonia gas and sodium nitrate.

[Fable]

you mean gas like NH3? so like not the NH3OH?

[YT2095]

the problem is this: NH3 + H2O = NH4(+) + OH(-)

 

NH4OH doesn`t Really exist, you will get NH3 gas from that reaction OR ammonia solution (depending on temp and pressure).

[Riogho]

You could get some shmexy ammonium

[Fable]

ammonia soulution, thats new for me. must refresh my literature to be up-to-date. thank you. so the solution exist only in lower temp.? is that correct? and if risen would make the ammonia 'pop' out?

[2nd]

Can I use electrical cell method

Solution of (NH3 + 2HOH) ---> (NH4OH) + H+ (Out on Anode?)

 

I just want to mix NH4OH with KNO3 to get NH4NO3

 

I didn't find any way