Where's the insoluble product?

[kimchee918]

hi

I'm stuck on several problems that involve writing the net ionic eq's given the reactants.

Obviously, all alkali metals are soluble no-matter-what, overruling insoluble rules. So given the eq KOH + RBH2PO4, would there be no reaction? Or, what would be the correct way to write the equation? My teacher said that all eq's react, meaning there's no 'no reaction'

Also, does rubidium dihydrogenphosphate = RbH2PO4?

Thanks in advance.

[CaptainPanic]

last things first:

yes, rubidium dihydrogenphosphate = RbH2PO4

 

In the reaction:

KOH + RBH2PO4, 2 things will happen:

 

1. it will dissolve, you can call that a reaction if you like:

KOH -> K+ + OH-

RbH2PO4 -> Rb+ + H2PO4-

 

2. OH- and H2PO4- will find a new equilibrium with H2O and HPO4(2-)

reaction: OH- + H2PO4- <--> H2O + HPO4(2-)

 

I'm glad you did not ask where the equilibrium is, because I'm lazy to calculate it. Check the acid/base theory for that.

 

p.s. next time, don't use abbreviations in your question. "eq" can be (reaction)equation, equilibrium.