joeyckn Posted January 16, 2008 Posted January 16, 2008 I'm sure that all of you know the experiment to find Ca2+ in ppm in a sample of hard water by titrating with edta using Eriochrome Black T as an indicator. During titration: H2Y2- (aq) + Ca2+ (aq) à CaY2- (aq) + 2 H+ (aq) H2Y2- (aq) + Mg2+ (aq) à MgY2- (aq) + 2 H+ (aq) At end point H2Y2- (aq) + MgIn- (aq) à MgY2- (aq) + HIn2- (aq) + H+ Wine-red sky-blue 1.The indicator reaction has to occur after the free Ca2+ or any free Mg2+ react. Why? 2.Hardness is traditionally expressed in mg CaCO3/L of water. Suppose that a water sample you analyzed contained mainly Mg2+, how would the calculation of hardness be affected? Explain. 3. Why [Mg-indicator]- is less stable than [Mg(edta)]2- and in turn less stable than [Mg-indicator]- ?? THX
Fuzzwood Posted January 29, 2008 Posted January 29, 2008 1. If it happens before, would you measure any calcium/magnesium? 2. If there isn't a lot of Ca2+, there wont be a lot of CaCO3. 3. You are contradicting yourself there.
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