Normal distribution

[ChemSiddiqui]

Alright I was doing some statistics questions and I have a probelm. Here goes:

 

The random variable Z is distributed such that Z

 

find the probalility:

 

P(lZl < 1.3) NB. < is actually less than equal to.

 

My solution:

 

P( -1.3< Z < 1.3)

 

P(z<1.3) - [ 1- P( Z < 1.3))

 

After putting values from the table

 

0.9032 - (1-0.9032).

 

0.9032 -0.9068 = -0.0036 (probalility can't be negative so my answer is wrong, mark scheme is saying the answer is 0.8064)

 

Thanks in advance.

[DrP]

 

The random variable Z is distributed such that Z

 

find the probalility:

 

P(lZl < 1.3) NB. < is actually less than equal to.

 

 

 

I think there should be more info.

[Bignose]

even with the missing info (which really is missing CS!), I think that 1-0.9032 is not 0.9068

[ChemSiddiqui]

Bignose I figured it out later that I was doing alright. The solution was right but my substraction wrong (I had put my calculator in a diffrent mode). Thanks any way.