computerages Posted February 29, 2008 Share Posted February 29, 2008 Hello, everyone, Following is the question that I am not really able to do. I would be grateful if someone can guide me through the solution. Thanks The electric-field strength as a function of position x in a certain region is given by [math]E = E_0 \left( {x/x_0 } \right)[/math], where [math]E0 = 26 {\rm kV/m}[/math] and [math]x_{0} = 5.2 {\rm m}[/math]. Find the total energy stored in a cube [math]1.0 {\rm m}[/math] on a side located between [math]x = 0[/math] and [math]x = 1.0\;{\rm{ m}}[/math]. Note: The field strength is independent of y and z. Link to comment Share on other sites More sharing options...
swansont Posted February 29, 2008 Share Posted February 29, 2008 How does potential energy relate to the electric field? Link to comment Share on other sites More sharing options...
computerages Posted March 1, 2008 Author Share Posted March 1, 2008 Hi, I derived this equation U=Eqr from V=U/q, and E=kq/r^2. But q is not given in the problem, where do I go from here? edit: I used the equation [math]U={1/2}{\varepsilon_{0}} \int E^{2}dV[/math] and E.F. equation given in the question to solve for U. After simplifying, I needed to compute the integral [math]\int_0^1 x^{2} dV[/math]. At first, I tried to have [math]dV[/math] in terms of [math]x[/math], but the answer was incorrect. Then I took the integral with respect to [math]x[/math] ignoring [math]dV[/math]. but I got the correct answer. Can anyone explain why I was able to compute the integral of [math]x^{2}[/math] without respect to [math]x[/math]... Thanks Can anyone answer my question, please. thanks Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now