computerages Posted February 29, 2008 Posted February 29, 2008 Hello, everyone, Following is the question that I am not really able to do. I would be grateful if someone can guide me through the solution. Thanks The electric-field strength as a function of position x in a certain region is given by [math]E = E_0 \left( {x/x_0 } \right)[/math], where [math]E0 = 26 {\rm kV/m}[/math] and [math]x_{0} = 5.2 {\rm m}[/math]. Find the total energy stored in a cube [math]1.0 {\rm m}[/math] on a side located between [math]x = 0[/math] and [math]x = 1.0\;{\rm{ m}}[/math]. Note: The field strength is independent of y and z.
swansont Posted February 29, 2008 Posted February 29, 2008 How does potential energy relate to the electric field?
computerages Posted March 1, 2008 Author Posted March 1, 2008 Hi, I derived this equation U=Eqr from V=U/q, and E=kq/r^2. But q is not given in the problem, where do I go from here? edit: I used the equation [math]U={1/2}{\varepsilon_{0}} \int E^{2}dV[/math] and E.F. equation given in the question to solve for U. After simplifying, I needed to compute the integral [math]\int_0^1 x^{2} dV[/math]. At first, I tried to have [math]dV[/math] in terms of [math]x[/math], but the answer was incorrect. Then I took the integral with respect to [math]x[/math] ignoring [math]dV[/math]. but I got the correct answer. Can anyone explain why I was able to compute the integral of [math]x^{2}[/math] without respect to [math]x[/math]... Thanks Can anyone answer my question, please. thanks
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