Maqboole Posted March 1, 2008 Posted March 1, 2008 Intergrate by parts: ∫ x(x +1)^4 dx X . ∫( x+1)^4 - ∫(∫(x+1)^4) . dy/dx (x) X. (X+1)^5 /5 - ∫(x+1)^5 /5 . 1 X. (X+1)^5 /5 – (x+1)^6 /30 +C. This is the best I can go. Our A’level teacher says its fine to do it till here, but the book has simplified answer I want to get to. Could someone tell me how to reach to the answer of (5X-1)(X+1)^5 /30 + C. Help appreciated !
D H Posted March 1, 2008 Posted March 1, 2008 The first two terms have a common factor of [math](x+1)^5[/math]: [math] \begin{split} x(x+1)^5/5 - (x+1)^6/30 + C =& \;(x+1)^5\left(\frac x 5 - \frac{x+1}{30}\right) +C \\ =& \;(x+1)^5\frac{(6x - (x+1)}{30} +C \\ =& \; \frac{(x+1)^5(5x - 1)}{30} +C \end{split} [/math]
ydoaPs Posted June 19, 2008 Posted June 19, 2008 [math][/math] tags allow you to use LaTeX on the forum.
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