Okay Chem Ppl!! Help!!

[crazziekid82]

i am stuck on this question and for the life of me i cant figure out how they got the answer!? here are the details i have

 

Preparation of a diluted soultion of household ammonia in which 20.00ml of household ammonia is diluted to 100.0ml dilution 5:1

 

Titrating the diulted ammonia with the standardised hydrochloric acid solution. in this step 20.00ml aliquots of dilute ammonia required 24.5l ml of hydrochloric acid for equivalence n(NH3) in 20 ml =1.177 x 10-2 mol

 

The percentage of ammonia NH3(aq) is household ammonia. Take the density of the household ammonia to be 1.08g mL-1..

the answer is 4.46%

 

However when you use the %= solute/ solution

doesn't give the right answer.... am i missing something?

[hermanntrude]

what answer do you get, then? perhaps you didnt take into account the 5:1 dilution?

[crazziekid82]

the final answer is 4.46%

[hermanntrude]

I meant what answer do you get when you do it your way (when you get a different answer to the correct one)?