Kyrisch Posted June 9, 2008 Posted June 9, 2008 I was trying to explain to a friend of mine why the time it takes for one swing of a pendulum is independent of both the mass on the end and the distance it is drawn back (for small angles, of course) but could not for the life of me remember the derivation of the equation for period of a simple harmonic oscillator [math] T = 2\pi\sqrt{\frac{-x}{a}}[/math]. Could someone help me out with this?
ecoli Posted June 9, 2008 Posted June 9, 2008 Isn't it given by trigonometry? http://en.wikipedia.org/wiki/Sine#Periodic_functions
Kyrisch Posted June 9, 2008 Author Posted June 9, 2008 From trigonometry it can be found that [math] x = -l[/math] and [math] a = g [/math] which makes the period for a pendulum [math] T = 2\pi\sqrt{\frac{l}{g}}[/math] but that doesn't help with that actual derivation of the general formula for period ([math]T = 2\pi\sqrt{\frac{-x}{a}}[/math]).
kevinalm Posted June 9, 2008 Posted June 9, 2008 Here's a link: http://farside.ph.utexas.edu/teaching/336k/lectures/node38.html Fitzpatrick explains it pretty well.
thedarkshade Posted June 9, 2008 Posted June 9, 2008 Yes, the period is indeed independent from the mass. It only varies from the length (directly) and gravitational attraction (indirectly), as Kyrisch's formula points out. You have have a clear picture of the pendulum, then I'll just move on to derivation" [math]F=mg\frac{x}{l}[/math] where x=elongation we know that F=ma, so: [math]ma=mg\frac{x}{l}[/math] so the masses cancel and then we're left with [math]a=mg\frac{x}{l}[/math] and as [math]a=\omega^2 x [/math] then: [math]\omega^2 x = g\frac{x}{l}[/math] again we cancel x on both sides and now you clearly see that we finally get [math]T=2\pi \sqrt{\frac{l}{g}}[/math] I hope this helpz, Shade!
swansont Posted June 9, 2008 Posted June 9, 2008 Note also the dependence on the small-angle approximation
kevinalm Posted June 9, 2008 Posted June 9, 2008 Generally speaking, the resonant frequency of a harmonic oscillator is only amplitude independant if the restoring force is linear, ie of the form F=-kx where k is a constant. Which of course is why a pendulum is amplitude dependant, the restoring force only satisfies this condition approximately, to the extent that the small angle aprx. sin x = x holds.
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