Can atom annihilate by 58 nuclear megatons to nothing?

[insane_alien]

well, i'm sure you have heard of einsteins equation E=mc^2

 

this is the perfect time to apply that equation(assuming negligible momentum in the system beforehand).

 

E is the energy released when a mass, m, is annihilated. as 1kg of antimatter annihilates with 1kg of normal matter, we have 2kg that gets converted to light.

 

the '2kg worth' just means the amount of light energy you'll get for converting 2kg of mass to energy. if i said it in joules it would be a very very large number. and also note that his doesn't mean that the light has a mass of 2kg.

[Edtharan]

and 2kg worth of photons.

Which would work out at (approximately): 180,000,000,000,000,000 joules

 

yeah, the 4kilos left over would likely be vaporised.

Yes, although a bit of an understatement. Not only would your 4kg be vaporised, but I think most of the Earth too.

[insane_alien]

not really, its only 94 Megatons. tsar bomba was designed to be 100 but scaled back to stop the fallout.

 

destructive sure but it would not destroy most of the earth. a 'little' crater of a few kilometers in diameter is most likely.

[Gilded]

Which would work out at (approximately): 180,000,000,000,000,000 joules

 

 

Yes, although a bit of an understatement. Not only would your 4kg be vaporised, but I think most of the Earth too.

 

Actually no, that's about 43 megatons, it wouldn't even be as powerful as Tsar Bomba. It'll be quite a while before we'll have antimatter weapons capable of vaporizing the Earth to any noticeable extent.

 

Edit: Huh? Where did you get your extra megatons from, insane_alien? Or did I mess up my calculations?

[insane_alien]

2kg of mass gets converted. its 43megatons/kg yeah?

[Mr Skeptic]

2kg of mass gets converted. its 43megatons/kg yeah?

 

Half of that, unless you are measuring just the antimatter.