absolute1 Posted August 1, 2008 Share Posted August 1, 2008 Dear friends, I come to you with great respect and the respect for our science legacy where countless work made up what we are today. I would like to propose to you a new view of gravity. A view that perhalf can bring us together. When one convert potential energy to kinetic energy, he or she use the formula mgh=1/2 m v^2 . Strickly speaking, mgh = Fd = Fh , where F=ma . If we do not use this method but rather use integration, one would write Work is mgh = [math]\int Fdh[/math] . One will find the same answer mgh because the integral of dh is h, and the force is constant. Now one will do the actual experimentation to verify this fact. He or she will find that the force is not constant through out the process for the same dh. This lead to a conclusion. The Work is not constant through out the process. It is greater than mgh. If the work is not constant, then there is only 1 solution. The mass is not constant through out the process. Kinetic energy is a true representation of the work, we then write 1/2 m v^2 = [math]\int Fdh[/math] = m(average)*a*h . m(average) = (1/2 m v^2)/(a*h) . We now can say that mass is a funciton of velocity and it grows exponentially with velocity. absolute1 Link to comment Share on other sites More sharing options...
Klaynos Posted August 1, 2008 Share Posted August 1, 2008 Your equation, E=mgh is incorrect. [math]E = -G \frac {m_1 m_2} {R}[/math] Have a read of: http://hyperphysics.phy-astr.gsu.edu/Hbase/gpot.html#ui If you work it out inside a vacuum, you will infact conclude that the energy close to the earth surface is mgh, saying that "Now one will do the actual experimentation to verify this fact" wont verify it is a lie unless you've got better experimental evidence than has already been gathered. Which you don't. Link to comment Share on other sites More sharing options...
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