ionizing radiation in space

[Arch2008]

This is what we’re talking about:

http://en.wikipedia.org/wiki/Health_threat_from_cosmic_rays

 

It might be more prudent to have some sort of non-radioactive interactive device that demonstrated the effect of cosmic rays on tissue. Something like a cue ball hitting a rack of balls. I read in Astronomy magazine that even iron ions can be CRs and they rip through your brain cells like a wild bull in a china shop.

 

This is a link to a company working on what you originally asked, a spacecraft shield. The problem with a magnetic shield is that this also creates a health risk to the crew.

http://engineering.dartmouth.edu/~Simon_G_Shepherd/research/Shielding/index.html

 

Here’s something else to think about:

http://thayer.dartmouth.edu/~Simon_G_Shepherd/research/Shielding/docs/Parker_05.pdf

 

The real problem with answering your question is that NASA has not answered it.

[Astronautical]

 

The way I'd do it, is to show experimentally that magnetic fields interact with moving charged particles in a ceratin way, which matches the equations (Lorentz Force), you can then use the equation to work out the size of the filed that would be required to deflect a particle of energy of a cosmic ray, or solar wind.

 

You can then use the B = equation given here:

 

http://en.wikipedia.org/wiki/Electromagnet#Force_on_ferromagnetic_materials

 

You can work out how big the electromagnet you'd need to generate a field that large...

 

 

 

How would I be able to calculate the energy of the electron gun and convert that to the energy of the actual energy?

 

Thanks.

 

This is what we’re talking about:

http://en.wikipedia.org/wiki/Health_threat_from_cosmic_rays

 

It might be more prudent to have some sort of non-radioactive interactive device that demonstrated the effect of cosmic rays on tissue. Something like a cue ball hitting a rack of balls. I read in Astronomy magazine that even iron ions can be CRs and they rip through your brain cells like a wild bull in a china shop.

 

This is a link to a company working on what you originally asked, a spacecraft shield. The problem with a magnetic shield is that this also creates a health risk to the crew.

http://engineering.dartmouth.edu/~Simon_G_Shepherd/research/Shielding/index.html

 

Here’s something else to think about:

http://thayer.dartmouth.edu/~Simon_G_Shepherd/research/Shielding/docs/Parker_05.pdf

 

The real problem with answering your question is that NASA has not answered it.

 

I never thought of the magnetic fields hurting the astronauts!

[Arch2008]

That’s why they call it rocket science.

 

After hours of diligent searching I stumbled onto this by sheer luck:

http://ksnn.larc.nasa.gov/21Century/pdf/p11_educator.pdf

It may be too simple for what you need, but may give you some ideas. Using a flashlight to simulate the radiation source is pretty easy.

[Astronautical]

That’s why they call it rocket science.

 

After hours of diligent searching I stumbled onto this by sheer luck:

http://ksnn.larc.nasa.gov/21Century/pdf/p11_educator.pdf

It may be too simple for what you need, but may give you some ideas. Using a flashlight to simulate the radiation source is pretty easy.

 

Thank you!

 

The more information I have the more preapared I will be.

 

Also, just a question on one of your previous posts.

What is the limit on the strength of a magnetic field before it starts causing harm to astronauts?

[Klaynos]

The energy of the electrons will be controlled by the voltage on the accelerating field in the electron gun... It might say on it, or say something that you can use to calculate teh velocity...

[Astronautical]

The energy of the electrons will be controlled by the voltage on the accelerating field in the electron gun... It might say on it, or say something that you can use to calculate teh velocity...

 

Alright cool, but how can I use the electron gun or the phosphor screen when it is out of the tv and not in the vacuum.

 

I was thinking I might have to put the elevtromagnet by the tv and the magnetic field should go through the glass and block the electrons from the inside.

 

I can prove it when one portion of the screen doesn't get a picture.

 

Or is there away to make these parts work outside of the tv?

 

Thanks.

[Arch2008]

Astronautical, the health risk level is unfortunately another unknown. Here is one link:

http://ohioline.osu.edu/cd-fact/0185.html

The problem is that astronauts would be living inside the magnetic "bubble" 24/7. No data exists for this level of exposure.

[Astronautical]

The energy of the electrons will be controlled by the voltage on the accelerating field in the electron gun... It might say on it, or say something that you can use to calculate teh velocity...

 

All I can see is a stamp that says these things

 

AC

 

120V (is this volts)

 

60Hz

 

28 W

 

EDIT: If any help it was manufactured in June 1987 and was built by KTV in Korea.

style number: KT1210A

 

 

 

How can I calculate the velocity (or v in this equation http://en.wikipedia.org/wiki/Lorentz_force) of the electron gun?

 

 

 

Also, for the Lorentz Force.I know to use this B = equation (http://en.wikipedia.org/wiki/Electromagnet#Force_on_ferromagnetic_materials) to find B (or the magnetic field in teslas ). But how do I find E which is the electric field in volts per meter?

 

Much thanks.

Edited August 10, 2008 by Astronautical
more information added

[NeonBlack]

All I can see is a stamp that says these things

 

AC

 

120V (is this volts)

 

60Hz

 

28 W

 

EDIT: If any help it was manufactured in June 1987 and was built by KTV in Korea.

style number: KT1210A

 

 

 

How can I calculate the velocity (or v in this equation http://en.wikipedia.org/wiki/Lorentz_force) of the electron gun?

 

 

 

Also, for the Lorentz Force.I know to use this B = equation (http://en.wikipedia.org/wiki/Electromagnet#Force_on_ferromagnetic_materials) to find B (or the magnetic field in teslas ). But how do I find E which is the electric field in volts per meter?

 

Much thanks.

 

You probably need to look inside for the accelerating voltage, which will typically be 10000 volts or higher. Then you know the kinetic energy will be [math]E=eV[/math], where e is the electron charge. Now, calculate the speed.

[Astronautical]

You probably need to look inside for the accelerating voltage, which will typically be 10000 volts or higher. Then you know the kinetic energy will be [math]E=eV[/math], where e is the electron charge. Now, calculate the speed.

 

I think I am confused about this.

 

Can you show me how to do it if was 10000 volts please?

 

I just do not see where you are plugging in what number?

 

Thanks.

 

EDIT: Also, how do I calculate the electric field?

[NeonBlack]

[math]KE=1.6\cdot10^{-19}C \cdot 10000V=1.6\cdot10^{-15}J[/math]

 

Calculate the speed from the kinetic energy.

 

Calculating electric field can be complicated. In general, [math]\vec{E}=\vec{\bigtriangledown}V[/math]

This probably isn't going to help you. If we assume that the potential is created from two (relatively) large parallel plates, then the electric field is a constant, [math]E=V/d[/math], where d is the distance between the plates.

Edited August 11, 2008 by NeonBlack
fixing latex

[Astronautical]

[math]KE=1.6\cdot10^{-19}C \cdot 10000V=1.6\cdot10^{-15}J[/math]

 

Calculate the speed from the kinetic energy.

 

Calculating electric field can be complicated. In general, [math]\vec{E}=\vec{\bigtriangledown}V[/math]

This probably isn't going to help you. If we assume that the potential is created from two (relatively) large parallel plates, then the electric field is a constant, [math]E=V/d[/math], where d is the distance between the plates.

 

You do not put a negative sign in fron of the electron's charge, correct?

 

I am just having trouble at this time of night I'm sorry.

 

How do I calculate the speed from the kinetic energy?

 

There are no plates. I am using a home-made electromagnet. With a battery and a nail and coils.

 

So how would I do it then?

[NeonBlack]

Sorry, yes I was being lazy with negative signs but in the end, the sign does not matter.

I hope you have seen [math]E=\frac{1}{2}mv^2[/math] before. If you have trouble with this, you will not be able to do the math required for the rest of this project.

There needs to be some type of plates inside the electron gun. A battery and coils will not make an electric field. Is it magnetic field you want to calculate? Magnetic field will not affect the speed of the electron, only the direction.

[Astronautical]

Sorry, yes I was being lazy with negative signs but in the end, the sign does not matter.

I hope you have seen [math]E=\frac{1}{2}mv^2[/math] before. If you have trouble with this, you will not be able to do the math required for the rest of this project.

There needs to be some type of plates inside the electron gun. A battery and coils will not make an electric field. Is it magnetic field you want to calculate? Magnetic field will not affect the speed of the electron, only the direction.

 

Oh duh. I guess it had just slipped me. Thanks!

 

Well only the direction would be effective for protecting astronauts correct because it would repel the electrons. I don't see the purpose of the electric field.

 

Also, just to be sure I can use http://en.wikipedia.org/wiki/Electromagnet#Force_on_ferromagnetic_materials this correctly.

 

Even if it is only a magnetic field and not an electromagnetic field both are powered by an electromagnet?

 

Because an electromagnet is just a magnet that is powered by electricity.

 

Why wouldn't it create a magnetic and electric field?

 

 

The way I'd do it, is to show experimentally that magnetic fields interact with moving charged particles in a ceratin way, which matches the equations (Lorentz Force), you can then use the equation to work out the size of the filed that would be required to deflect a particle of energy of a cosmic ray, or solar wind.

 

You can then use the B = equation given here:

 

http://en.wikipedia.org/wiki/Electromagnet#Force_on_ferromagnetic_materials

 

 

 

You can work out how big the electromagnet you'd need to generate a field that large...

 

 

 

I am going by this Lorentz Force and one of the variables is E (electric field in volts per meter). Do I need to find an equation for just magnettic fields not electromagnetic fields?

Edited August 11, 2008 by Astronautical
multiple post merged

[Klaynos]

If you're not applying an E field (which you're probably not) just put E=0 into the Lorentz equation... so I think the equation becomes

 

[math]F = q \bold v \times \bold B [/math]

[Astronautical]

If you're not applying an E field (which you're probably not) just put E=0 into the Lorentz equation... so I think the equation becomes

 

[math]F = q \bold v \times \bold B [/math]

 

Ah thank you.

[NeonBlack]

I think there may be some confusion regarding the electric/magnetic fields involved and I'm sorry. There needs to be an electric field (change in potential) inside the electron gun. This will be the 10000 volts. Without this, the electrons cannot move at high speeds. Outside of the electron gun, there will be a magnetic field (created by your electromagnet). Although the electro magnet is powered by electric current, there will not be any electric field unless you have regions of non-zero charge density (nominally, charged plates or something similar).

[Klaynos]

I think there may be some confusion regarding the electric/magnetic fields involved and I'm sorry. There needs to be an electric field (change in potential) inside the electron gun. This will be the 10000 volts. Without this, the electrons cannot move at high speeds. Outside of the electron gun, there will be a magnetic field (created by your electromagnet). Although the electro magnet is powered by electric current, there will not be any electric field unless you have regions of non-zero charge density (nominally, charged plates or something similar).

 

A clarification that was probably needed, sorry for being unclear