xXxAuroraxXx Posted April 12, 2004 Posted April 12, 2004 3 Guys walk into a hotel The person at the counter says it's 30$ for a room for all 3 of them The 3 guys pay 10$ each to split up the cost evenly Later on the night the manager knocks on there door and says he made a mistake and it was only 25$ for the room. He gives them back 5$ Each of the guys take 1$ and give the remaining 2$ to the bell boy. So, each person payed 9$ total 9*3 = 27$ + the 2$ for the bell boy = 29$ What happened to the remaining dollar?
Dave Posted April 12, 2004 Posted April 12, 2004 It's not really a math question - it's more of a trick question. The total cost for each of the men is $9 => $27 total price, yes. But that includes a $2 tip from their original money - there is no missing dollar.
xXxAuroraxXx Posted April 12, 2004 Author Posted April 12, 2004 I don't understand your answer... please explain it a little more. I asked this to my math teacher last year and she said it was an insolvable math problem.
Dave Posted April 12, 2004 Posted April 12, 2004 Erm, it's certainly not unsolvable. Think about this a little; at the beginning of the problem, the men give $30 to the hotel. At the end of the problem, they've given $2 to the bellboy, and they've each paid $9 ($27 in total). The question says: So, each person payed 9$ total 9*3 = 27$ + the 2$ for the bell boy = 29$ This isn't the calculation you should be doing - infact, it's pretty meaningless. The men paid $27 total, and the bellboy pocketed $2 from that $27, which means the men paid $25 (the price of the room) plus the tip ($2). This is a pretty old problem tbh. I've tried to explain it by taking the wording a little bit from here, that has a couple other approaches that might enable you to get to grips with it a bit more.
xXxAuroraxXx Posted April 12, 2004 Author Posted April 12, 2004 whoaaa wait. The 2$ was in their change....not the original amount they paid.
NSX Posted April 12, 2004 Posted April 12, 2004 dave, I was looking through the site you put up, how would you explain this: There are actually no negative numbers Did you know there are actually no negative numbers? Think about it, have you ever actually seen a negative number of geese? Ever wonder why? It's not what you think! The reason there are no negative numbers is simply that -1 is just another way of writing 1. Watch, I can prove it. I'll even explain it as I go along. Certainly, you'll have to allow me to start with -1 = -1 Then, if I divide both sides by 1, I get -1/1 = -1/1 Now, we know that -x/y = -(x/y) = (-x)/(y) = (x)/(-y). It doesn't matter where you put the minus sign. So, from that we get -1/1 = 1/-1 And, if we take the square root of both sides, we get root(-1/1) = root(1/-1) But we can split the square roots out, so root(-1) / root(1) = root(1) / root(-1) Now, we can cross multiply (to get rid of the fractions), and get root(-1) * root(-1) = root(1) * root(1) But surely root(x) * root(x) = x. That's the definition of root(x), so -1 = root(-1) * root(-1) = root(1) * root(1) = 1 Which leaves us with -1 = 1 Which is what I told you originally. So you can see that there really are no negative numbers. If you don't agree, try examining the proof closely. You can see I supported each step along the way. for me, it's the part with -x/y = -(x/y) = (-x)/(y) = (x)/(-y) 1
Dave Posted April 12, 2004 Posted April 12, 2004 Okay, let's look at it another way. Look at the total amounts spent and received. The hotel received $30 and paid a $5 refund; totals $25 gain. The men spent $30, received a $5 refund then paid $2 to the bellboy; totals $27 deficit - this includes the $2 spent paying the bellboy, so the men actually spent $25 on the room, and $2 tipping the bellboy.
ph1sher Posted April 12, 2004 Posted April 12, 2004 end situation: manager has 25 guys have 3 bellboy has 2 total of 30 the 27+2 calculation is erroneous since you are adding the tip twice. it should be that the men spent 27 (25 to the manager and 2 to the bellboy) but are now holding onto 3.
Dave Posted April 12, 2004 Posted April 12, 2004 for me, it's the part with [b']-x/y = -(x/y) = (-x)/(y) = (x)/(-y)[/b] I think either that, or the fact he's taking square roots of negative numbers and odd things can happen.
ph1sher Posted April 12, 2004 Posted April 12, 2004 dave' date=' I was looking through the site you put up, how would you explain this: for me, it's the part with [b']-x/y = -(x/y) = (-x)/(y) = (x)/(-y)[/b] i think the proof is invalid because root(x/y)=(root x)/(root y) only works where x and y are both positive. The principle does not hold, and thus invalidates this proof, when there are negative numbers.
NSX Posted April 12, 2004 Posted April 12, 2004 When the 5 dollar discount was given, it meant that the bill came to $25, making each person pay (25/3) = $8.33. The manager took 2 bucks and gave back 3, meaning the bill came to $28 (25 + 3), making each person pay (28/3) = $9.33. Therefore, (9.33*3) + 2 = 30.
mossoi Posted April 12, 2004 Posted April 12, 2004 That's not quite right. The manager took 2 bucks and gave back 3 which means that the bill came to $27 (25 + 2) not $28. Each man paid $9 (27/3) to cover both the room and the tip. The answer to this incarnation of this problem is in the error here: "So, each person payed 9$ total 9*3 = 27$ + the 2$ for the bell boy = 29$" ------------------------------------------------^ It should read: Each person paid $9 (total 9*3 = $27) to cover the room and the tip and was refunded $1 (total 1*3 = $3). 27 + 3 = $30 The discrepancy comes from the original problem including the bellboy's tip twice.
Sayonara Posted April 12, 2004 Posted April 12, 2004 We've already done this one twice. Because it's so damned old
xXxAuroraxXx Posted April 12, 2004 Author Posted April 12, 2004 Heh, good job Dave. The money is all there. There isn't a missing dollar, it's just a matter of how you word it.
Dave Posted April 12, 2004 Posted April 12, 2004 Yeah. You really have to watch the wording of the question; one slight little misphrase and it throws you off very easily (as shown quite nicely in this question).
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