Why not 1 ?

[Yuri Danoyan]

In discussion between L. B. Okun, G. Veneziano and M. J. Duff, concerning the number of fundamental dimensionful constants in physics (physics/0110060). They advocated correspondingly 3, 2 and 0 fundamental constants. Why they not considering case,where only 1 constant Planck-Dirac's constant; h/2pi=1,054x10^-27ergxsec?

This will be convincingly, because c- not contain mass dimension for triumvir and G overloading.and breaks 1/3 metasymmetry principle.

 

Pay attention to dimension L=01 T=11 (L- discrete,T- continue)

 

c ; L T^-1

 

G ; L^3 M^-1 T^-2 ; (1/3)^-2*M^-1

 

h ; L^2 M T^-1 ; 1/3*M

 

My be h only dimensionful constant of Nature? Some hint give Planck mass Mp=(hc/G)^1/2 .We simultaneously can decrease or increase c and G, but Mp remains unchanged.

 

As a consequence only Mp/Me=1836 true dimensionless constant?

Edited August 30, 2008 by Yuri Danoyan

[Yuri Danoyan]

IMHO Mpl only legal transaction,but not Lpl and Tpl, because they do not have a linear dependence between G AND c.

[Yuri Danoyan]

As we see in Planck-Dirac's constant:

h/2pi=1,054x10^-27ergxsec?

An other hand:

Space/Time 3:1;

Dark Energy/Dark Matter of the Universe approximately 3:1;

Why numerical coincidence of container and its contents?

As we see:

Energy correspond to Space.

Matter correspond to Time.

In Planck-Dirak constant Energy and Time vice versa connected by sign of multiplication.

Why?

[Bob_for_short]

...As a consequence only Mp/Me=1836 true dimensionless constant?

Right on the contrary: Me/Mp = 1/1836. It couples the proton and the relative electron-proton motions in Hydrogen.