Molarity problems

[nemzy]

If you put 25 mL of 1.6 M acetic acid, then, what is the molarity of acetic acid?

 

Is it just 1.6 M x .025 L, or is it .160 M / .025 L?

 

And..if you have 10 mL of 0.160 M sodium acetate , what is the moles of acetate in the solution?

 

Is it .160 M X .01 L,

 

im getting confused with the concepts involved in here

[Gampin]

25 mL of 1.6 M acetic acid :

 

0.025 L * 1.6 mol acetic acid / L = 0.04 mol acetic acid; for the molarity you have to b given volume of solvent the acetic acid will be dissolved in

 

10 mL of 0.160 M sodium acetate :

 

0.01 L * 0.16 mol sodium acetate / L = 0.0016 mol sodium acetate

[Crash]

looks correct to me;)