am24 Posted October 10, 2008 Posted October 10, 2008 Can you tell me if I've categorized these reactions correctly? It is quite possible that I didn't, so I'd love to hear from you! SN1: NaI + n-BuBr NaI + t-BuBr NaI + n-BuCl AgNO3 + n-BuCl AgNO3 + t-BuCl AgNO3 + n-BuBr AgNO3 + n-BuI SN2: NaI + i-BuBr NaI + s-BuBr AgNO3 + s-BuCl I was unsure of how to approach classifying the "normal" n substrates, so any help would be appreciated! Thank you so much for helping
big314mp Posted October 10, 2008 Posted October 10, 2008 "n" means a straight chain alkane (it stands for "normal"). Think about why a tertiary carbon goes through SN1, then go back and consider what is different between a tertiary carbon group and a "normal" carbon group.
lavoisier Posted October 10, 2008 Posted October 10, 2008 Hi am24, sometimes the boundary between SN1 and SN2 is a bit blurred. These exercises are OK for learning the concept, but in practice my advice is don't be too dogmatic about it. The basic message I think you need to grasp is that all the conditions that make the carbocation more stable favour the SN1 mechanism, and all those that make it more unstable favour SN2. It is known that carbocations can be stabilized by field effect (e.g. alkyl substituents - that's why tert-butyl cation is more stable than isopropyl cation) and by resonance (e.g. benzyl cation is more stable than cyclopropylmethyl cation). The better the leaving group, the easier the formation of the carbocation. In general, I->Br->Cl- for alkyl halides. Adding Ag+ favours the formation of the carbocation by making the halogen a better leaving group (because it can form a strong bond with the metal). In addition to that, the solvent can form interactions that stabilize the carbocations. And temperature plays a role too. Therefore, just writing down any two reagents and asking for a definite prediction of the mechanism is a bit pretentious. But there you go, I'm afraid you'll have to live with it as long as you're a student.
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