Tracker Posted November 16, 2008 Posted November 16, 2008 I am working on Taylor Series and I believe one of the derivatives in the solution manual is wrong. I am taking the derivative of [math] f(x) = \frac{x}{(1-x^2)^{(3/2)}} [/math] I believe it is: [math] f'(x) = \frac{1+2x^2}{(1-x^2)^2} [/math] but the answer key says it is: [math] f'(x) = \frac{1+2x^2}{(1-x^2)^{5/2}} [/math] Can you check my math please.
Cap'n Refsmmat Posted November 16, 2008 Posted November 16, 2008 I agree with the book's solution. I just worked it and got the same answer your solution manual has. Can you show us what you had just before you simplified the equation down to your final answer? I think you may have made an error in simplification.
Bignose Posted November 16, 2008 Posted November 16, 2008 Remember that taking the derivative for polynomial functions will decrease the exponent by a full unit. In this case something is to the power -3/2, after taking the derivative it will have to be the the power -5/2. If you didn't get something to the -5/2 power, then you made a mistake. Use the product rule and the chain rule and you should get the result the book printed.
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now