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Posted

Hello, my name is Rob and I am a part time college student, currently taking the lab portion of Organic Chemisty 2. I need help interpreting the mass spec of Isoamyl acetate (part of a homework assignment.)

 

The graph has a base peak at m/z = 43 which I understand to be the isopropyl portion and/or the ion consisting of a methyl attached to the carbonyl (can't think of the name of this.)

 

The graph also has two large peaks at m/z = 55 and 70. These, I do not understand. I assume that this molecule would undergo a McLafferty rearrangement, and the resulting alkene would have a weight of 70, but I thought that this alkene was always neutral. I suppose that if it's not, the 55 would be this ion minus a methyl, but I didn't think any of this happened, let alone formed the second and third biggest peaks.

 

In any case, can anyone help me with this?

Posted

Were the ions generated by PI or EI?

Anyway you are not completely off-track. m/z 43 is the acylium ion, and m/z 70 is the result from a heterolytic cleavage from the distonic ion.

So you have a gamma-H rearrangement, followed by the cleavage.

 

What also happens is a double H rearrangement (also called McLafferty+1), resulting in a weaker peak at m/z 61.

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