Chiron Posted December 8, 2008 Posted December 8, 2008 Hi, if somebody can give me some insight into this question, it would be greatly appreciated. A solution of vinegar is divided into 2 equal parts. Water is added to one part, while an equal volume of ethanol is added to the other. Do the two parts have the same pH? Why or Why not? If so, which solution is more acidic and why? So, I realize that there's something to do with pKa and the dissociation of ethanol when it is placed in water. When there's ionization, then, the pH will be adjusted. Am I on the right track?
hermanntrude Posted December 8, 2008 Posted December 8, 2008 I think you are on the right track. Which solvent (ethanol or water) is more likely to rip a proton (H+) off of acetic acid? Which product is more stable ([ce]CH3CH2OH2+[/ce] or [ce]H3O+[/ce])?
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