fafalone Posted November 7, 2002 Posted November 7, 2002 MIT Open Courseware for quantum mechanics: http://ocw.mit.edu/5/5.61/f01/index.html Go, learn, become less ignorant
aman Posted November 7, 2002 Posted November 7, 2002 It sound exciting. Thanks Fafalone for sharing it. I could use it and I can't get out much lately. Just aman
Radical Edward Posted November 9, 2002 Posted November 9, 2002 for a slightly less professional looking website. look here: http://www.lsr.ph.ic.ac.uk/~plenio/lecture.html beware though, this one is pretty heavy, as it is a 'foundations of quantum mechanics' course. - not for the faint hearted.
aman Posted November 10, 2002 Posted November 10, 2002 Thanks Radical E. It's hard to do much reading on a football weekend but maybe tonight. I'm feeling masochistic and love watching my ears smoke. Just aman
Tom Mattson Posted April 10, 2003 Posted April 10, 2003 Is anyone going through these? Would anyone like to, here in this thread? I will flesh out the details, if there is sufficient interest. Tom
Radical Edward Posted April 17, 2003 Posted April 17, 2003 Originally posted by Tom Is anyone going through these? Would anyone like to, here in this thread? I will flesh out the details, if there is sufficient interest. Tom well I intend to, though I am busy at the moment with my PhD. If someone could convert the lecture course from the link I posted into PDF an put it somewhere for me, I would be much appreciative, as I don't know what I need to read ps files.
fafalone Posted April 17, 2003 Author Posted April 17, 2003 Ghostscript/GSView I'm surprised you use LaTeX but haven't even heard of PS.
Radical Edward Posted April 17, 2003 Posted April 17, 2003 thanks, and I don't use LaTex. I have just heard of it, and I was wondering if anyone had opinions on it.
fafalone Posted April 17, 2003 Author Posted April 17, 2003 I prefer straight PDF. PS is the most typical type of LaTeX file, hence GSView is almost exclusively used to view LaTeX documents. There is a significant quality loss in converting to PDF, so you should really install GSView... but here it is: http://fafalone.hypermart.net/lectures.pdf
Tom Mattson Posted April 17, 2003 Posted April 17, 2003 Those notes are good. The only thing I would advise on is that they are clearly not meant for a first course in QM. On the other hand, the MIT Open Course Ware notes at the top of the thread are a first course. You might want to consider that when deciding which one you want to cover first. Tom
fafalone Posted April 18, 2003 Author Posted April 18, 2003 Of course basic training in physics is a prerequisite to either of those documents. If you think you understand QM but haven't learned basic physics, believe me you really don't know QM all too well.
Guest rick1138 Posted April 18, 2003 Posted April 18, 2003 Good notes! Nouredine Zettili's "Quantum Mechanics" is an excellent book with heavy duty math - it concentrates on the operator formalism, which is actually easy to use once you get used to it. Everything is explained in great detail, from both theoretical and practical perspectives, with proofs and solved problems.
Tom Mattson Posted April 18, 2003 Posted April 18, 2003 Originally posted by fafalone Of course basic training in physics is a prerequisite to either of those documents. If you think you understand QM but haven't learned basic physics, believe me you really don't know QM all too well. What I mean is, the MIT course would be a prerequisite for the last set of notes you posted. In more detail: MIT Course Prerequisites: Physics I/II (mechanics + EM), Calculus (differential + integral), Basic Linear Algebra, Basic Differential Equations Zettili Course Prerequisites: MIT QM Course, Advanced Calculus (including vector calculus, calculus of variations), Linear Algegra (including vector spaces), Differential Equations (including Fourier analysis, PDE), Abstract Algebra (especially groups) Tom
Guest rick1138 Posted April 18, 2003 Posted April 18, 2003 Yeah, you're right, I guess I've become comfortable enough with modern math that I prefer it to classical - I think the equations are easier to understand because what is being done is more cleanly seperated from the mechanics of doing it.
Dave Posted April 19, 2003 Posted April 19, 2003 Unfortunately I don't have the time yet. Too busy with exams and revision and stuff, but I did gloss over them and they seemed to be approachable with some work, so I'll probably do some work on it in the holidays after the exams.
Radical Edward Posted May 22, 2003 Posted May 22, 2003 right, I finally got round to starting to learn this stuff.... I have a question on p26 of the notes I posted, what is the meaning of |||x>|| is that just the magnitude of the vector? and why two lines rather than the conventional 1? thanks. oh, I am finding his discussion of completeness a bit tricks to follow as well, specifically the Cauchy Sequence.
Radical Edward Posted May 22, 2003 Posted May 22, 2003 in equation 1.54, where does he get Aij from? It looks to me like he gets it from <ej|fi> but then that would seem to make the whole derivation a bit redundant. in 1.56, would I be right in saying: fj|ej>=|ej>fj=|ej><ej|f> in other words: fj=<ej|f> sincethis is the scalar product of the orthonormal basis |ej> and |f>
Guest rick1138 Posted May 22, 2003 Posted May 22, 2003 on p26 of the notes I posted, what is the meaning of |||x>|| is that just the magnitude of the vector? and why two lines rather than the conventional 1? I'm not looking at the notes but the two lines usually means the norm, which in the context of a vector is the magnitude. Norm is a more general concept - it can refer to the "distance" between functions in function spaces, or any other mathematically consistent definition you can come up with. in equation 1.54, where does he get Aij from? It looks to me like he gets it from <ej|fi> but then that would seem to make the whole derivation a bit redundant. in 1.56, would I be right in saying: fj|ej>=|ej>fj=|ej><ej|f> in other words: fj=<ej|f> sincethis is the scalar product of the orthonormal basis |ej> and |f> <ej|fi> is an inner product |ej><ej| is an outer product |ej>fj is not allowed in Dirac notation <ej|fj is allowed if fj is an operator, or matrix, which I don't think it is <fj|ej> does equal <ej|fj>* where * stands for the complex conjugate
Radical Edward Posted May 23, 2003 Posted May 23, 2003 I will write the whole thing then: all the sums are from j=1 to N |f>=:sum:fj|ej>=:sum:|ej><ej|f> I can't figure out how he does it. I need more practise with this dirac notation.
Guest rick1138 Posted May 23, 2003 Posted May 23, 2003 I'm not sure which notes you mean. Zetteli's bookk is theh best place to learn ket-bra, and the Caltech notes are fairly good as well.
Radical Edward Posted May 23, 2003 Posted May 23, 2003 the ones I posted, like I said I have got a bit confused by him changing notation
Tom Mattson Posted May 23, 2003 Posted May 23, 2003 Originally posted by Radical Edward I will write the whole thing then: all the sums are from j=1 to N |f>=:sum:fj|ej>=:sum:|ej><ej|f> The leap from the first step to the second step is done by expanding |f> as a linear combination of the basis states |ej>. You can always expand an arbitrary vector in terms of basis states (that is the definition of basis states). So, you get: |f>=:sum:fj|ej>..........(1) where fj are complex numbers. The leap from the first to the third step is done with the projection operator. For a complete set of orthonormal basis states |ej>: :sum:|ej><ej|=1 where 1 is the unit operator. So, in this step: |f>=:sum:|ej><ej|f> all you are doing is multiplying |f> by 1, so the above is an identity. Since the <ej|f> are inner products of a bra-ket, they are complex numbers and can be moved to the left of the kets |ej>, like so: |f>=:sum:(<ej|f>)|ej>..........(2) (1) and (2) can be equated, and upon comparison it is seen that: fj=<ej|f> Tom
Tom Mattson Posted June 10, 2003 Posted June 10, 2003 Is anyone still following this thread? In any case, a just a note on this post... Originally posted by rick1138 |ej>fj is not allowed in Dirac notation <ej|fj is allowed if fj is an operator, or matrix, which I don't think it is You are correct in saying that fj is not an operator, but you are incorrect in saying that |ej>fj is not allowed. If you read my last post, you will see where I deduced that fj=<ej|f>. So, fj is just a complex number, and as such is allowed to stand on either the right or left hand side of a bra or ket.
NavajoEverclear Posted June 11, 2003 Posted June 11, 2003 Sounds cool, but I'm still busy with Navajo, and some other online HIGHSCHOOL classes. Yeah maybe when I get out of highschool
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