Gareth56 Posted December 15, 2008 Posted December 15, 2008 All was going swimmingly well reading my College Physics book by Serway until the dreaded simultaneous equation which I hope somebody can help me with. I can handling them except when there are letters involved. Find 'd' I managed to get to this point then collapsed! Units have been omitted for clarity. -d sin35deg = -0.5(9.81)((d cos35deg)/25)^2 Apparently d = 108m Thanks
Twerpy Posted December 16, 2008 Posted December 16, 2008 First simplify what you have a bit. The negative signs on each side cancel and multiply the two numbers on the right to get [math]dsin35 = (4.905)(\frac{dcos35}{25})^2[/math] then square the top and bottom of the fraction to give [math]dsin35 = (4.905)(\frac{d^2 cos^2 35}{625})[/math] cancel a d from each side: [math]sin35=(4.905)(\frac{dcos^2 35}{625})[/math] now it's just a case of rearranging and plugging it into a calculator which gives approximately 108. 1
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