Caligar Posted December 19, 2008 Share Posted December 19, 2008 (edited) Alright, I have a question. I've been working on this question with a friend for over an hour, and simply cannot get it. "A curve is parametrized by the equations x=square-root t, and y=(t-3)^2. Find an equation of the line tangent to the curve at the point defined by t=9" I know the answer is y=72x-180, because it is a study sheet, not actual homeowork. However, I need to understand how to do it for obvious reasons. Any help would be appreciated EDIT: Gaah, got it. We were taking the first derivative at the wrong time Delete please, Admins Edited December 19, 2008 by Caligar Link to comment Share on other sites More sharing options...
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