Caligar Posted December 19, 2008 Posted December 19, 2008 (edited) Alright, I have a question. I've been working on this question with a friend for over an hour, and simply cannot get it. "A curve is parametrized by the equations x=square-root t, and y=(t-3)^2. Find an equation of the line tangent to the curve at the point defined by t=9" I know the answer is y=72x-180, because it is a study sheet, not actual homeowork. However, I need to understand how to do it for obvious reasons. Any help would be appreciated EDIT: Gaah, got it. We were taking the first derivative at the wrong time Delete please, Admins Edited December 19, 2008 by Caligar
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